(2x-4)(x+3)=2x^2+18

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Solution for (2x-4)(x+3)=2x^2+18 equation: 



(2x-4)(x+3)=2x^2+18

We move all terms to the left:

(2x-4)(x+3)-(2x^2+18)=0

We get rid of parentheses

-2x^2+(2x-4)(x+3)-18=0

We multiply parentheses ..

-2x^2+(+2x^2+6x-4x-12)-18=0

We get rid of parentheses

-2x^2+2x^2+6x-4x-12-18=0

We add all the numbers together, and all the variables

2x-30=0

We move all terms containing x to the left, all other terms to the right

2x=30

x=30/2

x=15

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